Proof
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1. Proofs
A proof is a finite sequence of steps called logical deductions, which established the truth of a desired statement. More specifically, a proof is a sequence of statements where each successive statement is necessarily true if the previous statements were true.
2. Proof Techniques
2.1 Direct Proof
Approach:
Conclusion: \(P\implies Q\).
2.2 Proof by Contraposition
Recall that: \(P \implies Q \equiv \neg Q \implies \neg P\)
Approach:
Conclusion: \(\neg Q \implies \neg P\), so \(P \implies Q\).
Example:
- Prove Pigeonhole Principle.
2.3 Proof by Contradiction
To prove \(P\), we assume that \(P\) is false, and show that this leads to a conclusion which is A contradiction.
Approach:
Conclusion: \(\neg P \implies R \land \neg R\), which is a contradiction, i.e. \(\neg P \implies \text{False}\), so use contraposition we have \(\text{True} \implies P\), so \(P\).
Example:
- Prove there are infinite prime numbers.
- Prove \(\sqrt{2}\) is irrational.
2.4 Proof by Cases
Sometimes when we wish to prove a claim, we don't know which of a set of possible cases is true, but we know that at least one of them is true.
Example: Prove there exist irrational numbers \(x\) and \(y\) such that \(x^y\) is rational.
Proof: let \(x=\sqrt{2}\) and \(y=\sqrt{2}\). Make the following two cases:
- \(a\). \(\sqrt{2}^{\sqrt{2}}\) is rational.
- \(b\). \(\sqrt{2}^{\sqrt{2}}\) is irrational.
Because \(a\lor b\) is a tautology, exactly one of them must be true.
- If \(a\) is true, this immediately yields our claim, since \(x\) and \(y\) are both irrational and \(x^y\) is rational.
- If \(b\) is true, now we have a new irrational number \(\sqrt{2}^{\sqrt{2}}\). Let \(\sqrt{2}^{\sqrt{2}}\) and \(y=\sqrt{2}\), Then,
Now we again started with two irrational numbers \(x\) and \(y\) and obtained rational \(x^y\).
2.5 Mathematical Induction
See induction.
3. Common Error
- Don't assume the claim aim to prove. If we want to prove \(P\), we shouldn't assume \(P\) is true and implies a tautology. For example, if we want to prove \(-2=2\), we assume it and implies \(4=4\), which is true, but the proof makes no sense.
- Never forget to consider whether you divide by zero.
- Don't forget to flip the direction of the inequality when multiplying a negative number.